The second marble is blue given the first marble is red.
The probability that the second marble is blue.
A draw a tree diagram with probabilities to represent the sample space.
The probability of the second marble being blue is 4 19 since we have 1 less marble but not 1 less blue marble.
6 orange marbles 8 blue marbles and 6 white marbles.
Answer by stanbon 75887 show source.
P b 2 b 1 2 11.
P a b 7 12 5 11.
The probability of selecting a red marble on the first draw is 0 5.
Because the first marble is replaced the size of the sample space 9 does not change from the first drawing to the second so the events are independent.
Probability of the secod marbel being blue given the first one was blue is.
One marble is removed from the box and then replaced.
Two marbles are drawn without replacement.
The probability of the intersection of a and b is.
The probability is.
P b 2 p b 2 b 1 p b 2 g 1 p b 2 r 1 thus.
So i got rd 1 4 and blue 1 7 so 1 4 1 7 1 28 but my choices are 1 8 b.
The probability that the first marble is red is 5 20 or 1 4.
The probability of selecting a red marble and then a blue marble is 0 28.
1 4 c 1 7 or d.
If we got a blue marble before then the chance of a blue marble next is 1 in 4.
If we got a red marble before then the chance of a blue marble next is 2 in 4.
This is because we are removing marbles from the bag.
The probability is.
2 7 so i am not sure what i am doing wrong.
You can put this solution on your website.
P b 1 1 4.
And the probability that the third marble is white is 11 18 because we ve already chosen 2 marbles.
Another marble is drawn from the box.
C find the probability that two white marbles are drawn.
2 marbles are drawn without replacement from a box of 3 white 2 green 2 red and 1 blue marble.
Probability of the first marbel being blue is.
P b 2 3 12 2 11 4 12 3 11 5 12 3 12.
Now find the probability that the second marble is blue this is p b.
So the next event depends on what happened in the previous event and is called dependent.
A bag contains red and blue marbles.